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A charged particle (charge q) is moving...

A charged particle (charge `q`) is moving in a circle of radius `R` with unifrom speed `v`. The associated magnetic moment `mu` is given by

A

`(qvR)/(2)`

B

`qvR^(2)`

C

`(qvR^(2))/(2)`

D

`qvR`

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The correct Answer is:
To find the magnetic moment (μ) associated with a charged particle (charge `q`) moving in a circular path of radius `R` with uniform speed `v`, we can follow these steps: ### Step-by-Step Solution: 1. **Determine the Time Period (T)**: The time taken for the charged particle to complete one full revolution in a circular path is given by the formula: \[ T = \frac{2\pi R}{v} \] where `R` is the radius of the circle and `v` is the uniform speed of the particle. 2. **Calculate the Current (I)**: The current `I` associated with the moving charge can be defined as the charge passing through a point in one second. It is given by: \[ I = \frac{q}{T} \] Substituting the expression for `T` from step 1, we have: \[ I = \frac{q}{\frac{2\pi R}{v}} = \frac{qv}{2\pi R} \] 3. **Determine the Area (A)**: The area `A` enclosed by the circular path of the charged particle is given by: \[ A = \pi R^2 \] 4. **Calculate the Magnetic Moment (μ)**: The magnetic moment `μ` is defined as the product of the current and the area through which it flows: \[ \mu = I \cdot A \] Substituting the expressions for `I` and `A`, we get: \[ \mu = \left(\frac{qv}{2\pi R}\right) \cdot (\pi R^2) \] Simplifying this expression: \[ \mu = \frac{qvR}{2} \] Thus, the associated magnetic moment `μ` for the charged particle moving in a circle of radius `R` with uniform speed `v` is: \[ \mu = \frac{qvR}{2} \]

To find the magnetic moment (μ) associated with a charged particle (charge `q`) moving in a circular path of radius `R` with uniform speed `v`, we can follow these steps: ### Step-by-Step Solution: 1. **Determine the Time Period (T)**: The time taken for the charged particle to complete one full revolution in a circular path is given by the formula: \[ T = \frac{2\pi R}{v} ...
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