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A galvanometer of resistance G is shunt...

A galvanometer of resistance `G` is shunted by a resistance `S ohm`. To keep the main current in the circuit uncharged, the resistnace to be put in series with the galvonmeter

A

`(S^(2))/((S + G))`

B

`(SG)/((S + G))`

C

`(G^(2))/((S + G))`

D

`(G)/((S + G))`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the resistance to be put in series with a galvanometer of resistance \( G \) that is shunted by a resistance \( S \) ohm, we can follow these steps: ### Step 1: Understand the Circuit Configuration We have a galvanometer with a resistance \( G \) and a shunt resistance \( S \) connected in parallel to it. The total current flowing through the circuit should remain unchanged when the shunt is added. ### Step 2: Apply the Concept of Equivalent Resistance When the galvanometer and the shunt are connected in parallel, the equivalent resistance \( R_{eq} \) of the parallel combination can be calculated using the formula: \[ \frac{1}{R_{eq}} = \frac{1}{G} + \frac{1}{S} \] This formula allows us to find the total resistance of the parallel circuit. ### Step 3: Calculate the Equivalent Resistance Rearranging the formula gives us: \[ R_{eq} = \frac{GS}{G + S} \] ### Step 4: Determine the Total Resistance in the Circuit Let \( R \) be the resistance that we need to add in series with the galvanometer. The total resistance \( R_{total} \) in the circuit will then be: \[ R_{total} = R + R_{eq} \] ### Step 5: Set Up the Condition for Unchanged Current To keep the main current in the circuit unchanged, the total resistance must remain equal to the original resistance \( R_{original} \) of the circuit without the shunt. Thus, we can write: \[ R + R_{eq} = R_{original} \] ### Step 6: Solve for the Series Resistance \( R \) Substituting \( R_{eq} \) into the equation gives: \[ R + \frac{GS}{G + S} = R_{original} \] From this, we can solve for \( R \): \[ R = R_{original} - \frac{GS}{G + S} \] ### Final Expression Thus, the resistance to be put in series with the galvanometer is: \[ R = R_{original} - \frac{GS}{G + S} \]

To solve the problem of finding the resistance to be put in series with a galvanometer of resistance \( G \) that is shunted by a resistance \( S \) ohm, we can follow these steps: ### Step 1: Understand the Circuit Configuration We have a galvanometer with a resistance \( G \) and a shunt resistance \( S \) connected in parallel to it. The total current flowing through the circuit should remain unchanged when the shunt is added. ### Step 2: Apply the Concept of Equivalent Resistance When the galvanometer and the shunt are connected in parallel, the equivalent resistance \( R_{eq} \) of the parallel combination can be calculated using the formula: \[ ...
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