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A magnet of magnetic moment M and pole s...

A magnet of magnetic moment M and pole strength m is divided in two equal parts, then magnetic moment of each part will be

A

`M`

B

`M//2`

C

`M//4`

D

`2M`

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The correct Answer is:
To solve the problem, we need to analyze the effect of dividing a magnet into two equal parts on its magnetic moment. The magnetic moment (M) of a magnet is given by the formula: \[ M = m \times L \] where: - \( m \) is the pole strength, - \( L \) is the length of the magnet. ### Step-by-Step Solution: 1. **Understanding the Initial Conditions**: - We have a magnet with a magnetic moment \( M \) and pole strength \( m \). - The length of the magnet is \( L \). - Therefore, the initial magnetic moment can be expressed as: \[ M = m \times L \] 2. **Dividing the Magnet**: - The magnet is divided into two equal parts. This can be done in two ways: - **Cutting along the length**: This means we cut the magnet into two halves along its length. - **Cutting perpendicularly**: This means we cut the magnet into two equal halves across its width. 3. **Case 1: Cutting Along the Length**: - When the magnet is cut along its length, each part will have: - Length of each part = \( \frac{L}{2} \) - Pole strength remains the same = \( m \) - The magnetic moment of each part (let's call it \( M_P \)) will be: \[ M_P = m \times \frac{L}{2} = \frac{mL}{2} \] - Since \( mL = M \), we can substitute: \[ M_P = \frac{M}{2} \] 4. **Case 2: Cutting Perpendicularly**: - When the magnet is cut perpendicularly, each part will have: - Length of each part = \( L \) (remains unchanged) - Pole strength of each part = \( \frac{m}{2} \) - The magnetic moment of each part (let's call it \( M_Q \)) will be: \[ M_Q = \frac{m}{2} \times L = \frac{mL}{2} \] - Again, substituting \( mL = M \): \[ M_Q = \frac{M}{2} \] 5. **Conclusion**: - In both cases, whether the magnet is cut along the length or perpendicularly, the magnetic moment of each part is \( \frac{M}{2} \). - Therefore, the magnetic moment of each part after division is: \[ \text{Magnetic moment of each part} = \frac{M}{2} \] ### Final Answer: The magnetic moment of each part after dividing the magnet into two equal parts is \( \frac{M}{2} \). ---

To solve the problem, we need to analyze the effect of dividing a magnet into two equal parts on its magnetic moment. The magnetic moment (M) of a magnet is given by the formula: \[ M = m \times L \] where: - \( m \) is the pole strength, - \( L \) is the length of the magnet. ...
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A2Z-MAGNETISM AND MATTER-Section D - Chapter End Test
  1. A magnet of magnetic moment M and pole strength m is divided in two eq...

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  2. The true value of angle of dip at a place is 60^(@), the apparent dip ...

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  3. A magnetic needle lying parallel to a magnetic field requires W units ...

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  4. A thin rectangular magnet suspended freely has a period of oscillation...

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  5. The length of a magnet is large compared to its width and breadth. The...

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  6. Two identical short bar magnets, each having magnetic moment M, are pl...

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  7. The magnet field lines due to a bar magnet are correctly shown in

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  8. A curve between magnetic moment and temperature of magnet is

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  9. Which curve may best repreasent the current deflection in a tangent ga...

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  10. The variation of the intensity of magnetisation (I) with respect to th...

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  11. For ferromagnetic material, the relative permeability (mu(r)), versus ...

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  12. A magnet is suspended horizontal in the earth's magnetic field. When i...

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  13. The field due to a magnet at a distance R~ from the centre of the magn...

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  14. A long magnet is cut in two parts in such a way that the ratio of thei...

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  15. If the magnetic flux is expressed in weber, then magnetiv induction ca...

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  16. Magnetic intensity for an axial point due to a short bar magnet of mag...

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  17. A small rod of bismuth is suspended freely between the poles of a stro...

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  18. Magnetic moment of two bar magnets may be compared with the help of

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  19. At place, the magnitudes of the horizontal component and total intensi...

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  20. The angle of dip at a certain place is 30^(@). If the horizontal compo...

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  21. The horizontal component of the earth's magnetic field is 0.22 Gauss a...

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