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A magnet of length 0.1 m and pole streng...

A magnet of length `0.1 m` and pole strength `10^(-4)` A.m. is kept in a magnetic field of `30 Wb//m^(2)` at an angle `30^(@)`. The couple acting on it is `…xx10^(-4)Nm`.

A

`7.5`

B

`3.0`

C

`1.5`

D

`6.0`

Text Solution

Verified by Experts

The correct Answer is:
C
`tau=MB sin theta=mxx(2l)xxB sintheta`
`=10^(-4)xx0.1xx30 sin 30^(@)=1.5xx10^(-4) Nm`
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Knowledge Check

  • A magnet of length 0.1 m and pole strength 10(-4) Am is kept in a magnetic field of 30 Wb"/"m^(2) at an angle of 30^(@) The couple acting on it is ... xx 10^(-4) Nm

    A
    7.5
    B
    1.5
    C
    4.5
    D
    6

  • The magnetic moment of a length 10 cm and pole strength 4.0 Am will be

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    `0.4 Am^(2)`
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    `1.6 Am^(2)`
    C
    `20 Am^(2)`
    D
    `8.0 Am^(2)`

  • Torque acting on a magnet of length 0 cm and pole strength 15 km-m kept in a field of B = 2 xx 10^(-5) T at an angle of 30^(@) is

    A
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    B
    `1.5 xx 10^(-3) N-m`
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