At a certain place, the horizontal component of earth's magnetic field is `sqrt(3)` times the vertical component. The angle of dip at that place is

Options

A. `60^(@)`
B. `45^(@)`
C. `90^(@)`
D. `30^(@)`

Explanation

To find the angle of dip at a place where the horizontal component of the Earth's magnetic field (BH) is \(\sqrt{3}\) times the vertical component (BV), we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Relationship**:
The angle of dip (denoted as \(\delta\)) is related to the horizontal and vertical components of the Earth's magnetic field by the formula:
\[ \tan(\delta) = \frac{BV}{BH} \]

2. **Substitute the Given Values**:
According to the problem, we have:
\[ BH = \sqrt{3} \times BV \]
We can substitute this into the equation for the angle of dip:
\[ \tan(\delta) = \frac{BV}{\sqrt{3} \times BV} \]

3. **Simplify the Equation**:
The \(BV\) terms in the numerator and denominator cancel out:
\[ \tan(\delta) = \frac{1}{\sqrt{3}} \]

4. **Determine the Angle**:
We know from trigonometric values that:
\[ \tan(30^\circ) = \frac{1}{\sqrt{3}} \]
Therefore, we can conclude:
\[ \delta = 30^\circ \]

5. **Final Answer**:
The angle of dip at that place is \(30^\circ\).