The dip at a place is delta. For measuring it, the axis of the dip needle is perpendicular to the magnetic meridian. If the axis of the dip needle makes angle `theta` with the magnetic meridian, the apparent dip will be given `tan delta_(1)` which is equal to:

Options

A. `tan delta cos theta`
B. `tan delta sec theta`
C. `tan delta sin theta`
D. `tan delta cosec theta`

Answer

B

Explanation

`tan delta=B_(V)/B_(H) and tan delta_(1)=B_(V)/(B_(V) costheta)`
or `tan delta _(1)=(tan delta)/(cos theta)=tan delta sec theta`