A thin magnetic needle oscillates in the horizontal plane with a time period of 2.0 sec. If the needle is broken into 4 equal parts perpendicular to its length, then the time period of each part will be:

Options

A. `0.5 s`
B. `1.0 s`
C. `1.5 s`
D. `2.0 s`

Answer

A

Explanation

`T=2pisqrt((1)/(MB))`
For each part M becomes one-fourth while I becomes `(1//64)th`.
Hence, `T^(')=sqrt((I//64)/((M//4)))=T/4=2/4=0.5 sec`