The dipole moment of each molecule of a paramagnetic gas is `1.5xx10^(-23) amp xx m^(2)`. The temperature of gas is `27^(@)` and the number of molecules per unit volume in it is `2xx10^(26)m^(-3)`. The maximum possible intensity of magnetisation in the gas will be

Options

A. `3xx10^(3) amp//m`
B. `4xx10^(-3) amp//m`
C. `5xx10^(5) amp//m`
D. `6xx10^(-4) amp//m`

Answer

A

Explanation

`I=M/V=(muN)/V=(1.5xx10^(-23)xx2xx10^(26))/1=3xx10^(3) Amp//m`