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The area of hysteresis loop of a materia...

The area of hysteresis loop of a material is equinalent to 250 joule. When 10 kg material is magnetised by an alternating field of 50 Hz then energy lost in one hour will be if the density of material is `7.5 gm//cm^(2)`

A

`6xx10^(4)J`

B

`6xx10^(4)erg`

C

`3xx10^(2)J`

D

`3xx10^(2)erg`

Text Solution

Verified by Experts

The correct Answer is:
A
`E=nAVt=nAm/dt=(50xx250xx10xx3600)/(7.5xx10^(3))=6xx10^(4)`
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