An inductance `L` and a resistance `R` are first connected to a battery. After some time the battery is disconnected but `L` and `R` remain connected in a closed circuit. Then the current reduces to `37%` of its initial value in

Options

A. `RL sec`
B. `(R )/(L)`sec
C. `(L)/(R )`sec
D. `(1)/(LR)`sec

Answer

C

Explanation

When battery disconnected current through the circuit start decreasing exponentially according to`i=i_(0)e^(-Rt//L)`.
`implies0.37i_(0)=i_(0)e^(-Rt//L)implies0.37=(1)/(e)=e^(-Rt//L)impliest=(L)/(R )`