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In series with 20 ohm resitor a 5 henry ...

In series with `20 ohm` resitor a `5` henry inductor is placed. To the combination an e.m.f. of `5` volt is applied. What will be the rate of increase of current at `t=0.25 sec`?

A

`e`

B

`e^(-2)`

C

`e^(-1)`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C
`i=i_(0)(1e^(-Rt//L))implies(di)/(dt)=i_(0)((R )/(L))e^(-Rt//L)=(E)/(L)e^(-Rt//L)`
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