In the current shown Fig., `X` is joined to `Y` for a long time and then `X` is joined to `Z`. The total heat produced in `R_(2)` is

Options

A. `(LE^(2))/(2R_(1)^(2))`
B. `(LE^(2))/(2R_(2)^(2))`
C. `(LE^(2))/(2R_(1)R_(2))`
D. `(LE^(2)R_(2))/(2R_1^(3))`

Answer

A

Explanation

Steady-state current in `L=I_(0)=(E)/(R_(1))`
Energy stored in `L`
`=(1)/(2)LI_(0)^(2)=(1)/(2)L((E^(2))/(R_(1)^(2)))`
=heat produced in `R_(2)` during discharge.