Home
Class 12
PHYSICS
A motor having an armature of resistance...

A motor having an armature of resistance `2Omega` is designed to operate at `220 V` mains. At full speed, it devlops a back e.m.f. of `210V`. When the motor is running at full speed, the current in the armature is

A

`5A`

B

`105A`

C

`110A`

D

`215A`

Text Solution

Verified by Experts

The correct Answer is:
A

`i=(E-e)/(R )=(220-210)/(2)=(10)/(2)=5A`
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC INDUCTION

    A2Z|Exercise Problems On Mixed Concepts|37 Videos
  • ELECTROMAGNETIC INDUCTION

    A2Z|Exercise Section B - Assertion Reasoning|31 Videos
  • ELECTROMAGNETIC INDUCTION

    A2Z|Exercise Inductor Circuits|31 Videos
  • ELECTRIC POTENTIAL & CAPACITANCE

    A2Z|Exercise Section D - Chapter End Test|29 Videos
  • ELECTROMAGNETIC WAVES AND COMMUNICATION SYSTEM

    A2Z|Exercise Section D - Chapter End Test|30 Videos

Similar Questions

Explore conceptually related problems

A motor having an armature of resistance 2.0 Omega operates on 220 V mains. At full speed, it develops a back emf of 210 V. Find the current in the armature just when the motor is switched on (assuming that no starter is used) and when running at full speed. Also fined the efficiency of the motor at full speed.

A motor having an armature of resistance 2.0 ohm operates on 220 V mains. At its full speed, it develops a back e.m.f. of 210 V. Find the currents in the armature when motor is switched on and when running at full speed. What is the efficiency ot the motor at full speed ?

when the speed of a dc motor increase the armature current

A simple electric motor has an armature resistance of 1Omega and runs from a dc source of 12 volt . When running unloaded it draws a current of 2 amp . When a certain load is connected , its speed becomes one-half of its unloaded value . The new value of current drawn

A motor has an armature resistance of 4 ohm. On a 240 V supply and a light load, the motor speed is 200 rpm and the armature current is 5 A Calculate the motor speed at a full load. When armature current is 20 A.

A generator develops an e.m.f. of 120 V and has a terminal potential difference of 115 V, when the amature current is 25 A. What is the resistance of the armature ?

A coil has an inductance of 0.7 H and is joined in series with a resistance of 220 Omega . When an alternating e.m.f of 220 V at 50 c.p.s. is applied to it, then the wattless component of the current in the circuit is

A fan operates at 200 volt (DC) consuming 1000W when running at full speed . It's internal wiring has resistance 1 Omega . When the fan runs at full speed , its speed becomes constant. This is because the torque due to magnetic field inside tha fan is balanced by the torque due to air resistance on the blades of the fan and torque due to friction between the fixed part and the shaft of the fan. The electrical power going into the fan is spent (i) in the internal resistance as heat, call it P_(1)(ii) in doing work against internal friction and air resistance producing heat, sound etc. call it P_(2) . When the coil of fan rotates, an emf is also induced in the coil. This opposes the external emf applied to snd the current into the fan. This emf is called back-emf,call it 'e' . Answer the following questions when the fan is running at full speed. The current flowing into the fan and the value of back emf e is

The armature of a generator of resistance 1Omega is rotated at its rated speed and produces 125 V without load and 115 V with full load. The current in the armature coil is

A2Z-ELECTROMAGNETIC INDUCTION-Applications Of Emi
  1. An electric motor operating on a 60 V dc supply draws a currrent of 1...

    Text Solution

    |

  2. An electric motor operating on a 60 V dc supply draws a currrent of 1...

    Text Solution

    |

  3. A motor having an armature of resistance 2Omega is designed to operate...

    Text Solution

    |

  4. A transformer is employed to

    Text Solution

    |

  5. What is increase in step-down transformer?

    Text Solution

    |

  6. The transformation ratio in the step-down transformer is

    Text Solution

    |

  7. In a transformer 220 ac voltage is increased to 2200 volts. If the nu...

    Text Solution

    |

  8. The ratio of secondary to the primary turns in a transformer is 3:2. I...

    Text Solution

    |

  9. The primary winding of a transformer has 100 turns and its secondary w...

    Text Solution

    |

  10. A step-down transformer is connected to 2400 volts line and 80 amperes...

    Text Solution

    |

  11. A loss free transformer has 500 turns on its primary winding and 2500 ...

    Text Solution

    |

  12. An ideal transformer has 100 turns in the primary and 250 turns in the...

    Text Solution

    |

  13. A transformer is employed to reduce 220V to 11V. The primary draws a ...

    Text Solution

    |

  14. in a step-up transformer, the turn ratio is 1:2A leclanche cell (e.m.f...

    Text Solution

    |

  15. A 100% efficient transformer has 100 turns in the primary and 25 turns...

    Text Solution

    |

  16. In a lossless transformer an alternating current of 2 amp is flowing i...

    Text Solution

    |

  17. A transformer connected to 220 volt line shows an output of 2A at 1100...

    Text Solution

    |

  18. The coils of a step down transformer have 500 and 5000 turns. In the ...

    Text Solution

    |

  19. A power transformer is used to step up an alternating e.m.f. of 220 V ...

    Text Solution

    |

  20. A step up transformer connected to a 220V AC line is to supply 22 kV f...

    Text Solution

    |