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In a lossless transformer an alternating...

In a lossless transformer an alternating current of `2` amp is flowing in the primary coil. The number of turns in the primary and secondary coils are `100` and `20` respectively. The value of the current in the secondary coil is

A

`0.08A`

B

`0.4A`

C

`5A`

D

`10A`

Text Solution

Verified by Experts

The correct Answer is:
D
`(N_(s))/(N_(p))=(i_(p))/(i_(s))impliesi_(s)=i_(p)xx(N_(p))/(N_(s))=2xx(100)/(20)=10A`
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