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An average induced e.m.f. of 1V appears ...

An average induced e.m.f. of `1V` appears in a coil when the current in it is changed from `10` `A` in one direction to `10A` in opposite direction in `0.5` sec. self-inductance of the coil is

A

`25mH`

B

`50mH`

C

`75mH`

D

`100mH`

Text Solution

Verified by Experts

The correct Answer is:
A
`|e|=L(di)/(dt)impliesI=(Lxx{10-(-10)})/(0.5)`
`impliesL=25mH`
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