The wing span of an aeroplane is `20` metre. It is flying in a field, where the verticle component of magnetic field of earth is `5xx10^(-5)` tesla, with velocity `360 km//h`. The potential difference produced between the blades will be

Options

A. `0.10V`
B. `0.15V`
C. `0.20V`
D. `0.30V`

Explanation

To find the potential difference produced between the blades of the aeroplane, we can use the formula for electromagnetic induction, which relates the induced electromotive force (emf) to the magnetic field, the velocity of the conductor, and the length of the conductor within the magnetic field.

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Wingspan (length of the conductor, L) = 20 m
- Vertical component of the magnetic field (B) = 5 x 10^(-5) T
- Velocity (v) = 360 km/h

2. **Convert Velocity to m/s:**
- To convert km/h to m/s, we use the conversion factor:
\[ 1 \text{ km/h} = \frac{1}{3.6} \text{ m/s} \]
- Therefore,
\[ v = 360 \text{ km/h} = \frac{360}{3.6} = 100 \text{ m/s} \]

3. **Use the Formula for Induced EMF:**
- The induced emf (E) can be calculated using the formula:
\[ E = B \cdot L \cdot v \]
- Substituting the values:
\[ E = (5 \times 10^{-5} \, \text{T}) \cdot (20 \, \text{m}) \cdot (100 \, \text{m/s}) \]

4. **Calculate the Induced EMF:**
- Performing the multiplication:
\[ E = 5 \times 10^{-5} \cdot 20 \cdot 100 \]
\[ E = 5 \times 20 \times 100 \times 10^{-5} \]
\[ E = 10000 \times 10^{-5} \]
\[ E = 1 \text{ V} \]

5. **Conclusion:**
- The potential difference produced between the blades of the aeroplane is **1 Volt**.