A long solenoid has `500` turns. When a current of `2A` is passed through it, the resulting magnetic flux linked with each turn of the solenoid is `4xx10^(-3)Wb` . The self-inductance of the solenoid is

Options

A. `2.5H`
B. `2.0H`
C. `1.0H`
D. `4.0H`

Answer

C

Explanation

Inductance of a coil is numerically equal to the emf induced in the coil when the current in the coil change at the rate orf `1As^(-1)`.
If `I` is the current flowing in the ciircuit, then flux linked with the circuit is observed to be proportional to `I`,i.e.,
`phipropI`
or `phi=LI`
where `L` is called the self-inductance or coefficient of self-inductance or simply inductance of the coil.
net flux through solenoid,
`phi=500xx4xx10^(-3)=2Wb`
or `2=Lxx2`
`["after putting values in Eq". (i)]`
or `L=1H`