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The current flowing in a coil of self-in...

The current flowing in a coil of self-inductance `0.4 mH` is increased by `250mA` in `0.1` sec. the e.m.f. induced will be

A

`+1V`

B

`-1V`

C

`+1mV`

D

`-1mV`

Text Solution

Verified by Experts

The correct Answer is:
D

`e=-L(di)/(dt)=-0.4xx10^(-3)xx(250xx10^(-3))/(0.1)=-mV`
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A2Z-ELECTROMAGNETIC INDUCTION-Section D - Chapter End Test
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