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A hundred turns of insulated copper wire...

A hundred turns of insulated copper wire are wrapped around an iron cylinder of area `1xx10^(-3) m^(2)` and are connected to a resistor. The total resistance in the circuit is `10` ohms. If the longitudinal magnetic induction in the iron changes from `1` weber `m^(-2)`, in one direction to `1` weber `m^(-2)` in the opposite direction, how much charge flows through the circuit

A

`2xx10^(-2)C`

B

`2xx10^(-3)C`

C

`2xx10^(-4)C`

D

`2xx10^(-5)C`

Text Solution

Verified by Experts

The correct Answer is:
A

`dQ=(dvarphi)/(R )=(nAdB)/(R )=(100xx1xx10^(-3)xx2)/(10)=2xx10^(-2)C`
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A2Z-ELECTROMAGNETIC INDUCTION-Section D - Chapter End Test
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