A metal conductor of length 1m rotates v...

A metal conductor of length 1m rotates vertically about one of its ends at angular velocity 5 radians per second. If the horizontal component of earth's magnetic field is `0.2xx10^(-4)T`, then the emf developed between the two ends of the conductor is

`5mV`

`5xx10V`

`50mV`

`50muV`

Text Solution

Verified by Experts

The correct Answer is:

`i=(1)/(2)Bomegar^(2)=(1)/(2)xx0.2xx10^(-4)xx5xx(1)^(2)=50muV`

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