A `40Omega` electric heater is connected to a `200V, 50Hz` main supply. The peak value of electric current flowing in the circuit is approx.

Options

A. `2.5A`
B. `5A`
C. `7A`
D. `10A`

Explanation

To find the peak value of the electric current flowing through a 40Ω electric heater connected to a 200V, 50Hz main supply, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Resistance (R) = 40Ω
- RMS Voltage (V_RMS) = 200V

2. **Calculate the RMS Current (I_RMS):**
The RMS current can be calculated using Ohm's Law:
\[ I_{RMS} = \frac{V_{RMS}}{R} \]
Substituting the values:
\[ I_{RMS} = \frac{200V}{40Ω} = 5A \]

3. **Convert RMS Current to Peak Current (I_peak):**
The peak current can be calculated from the RMS current using the relationship:
\[ I_{peak} = I_{RMS} \times \sqrt{2} \]
Substituting the value of I_RMS:
\[ I_{peak} = 5A \times \sqrt{2} \approx 5A \times 1.414 \approx 7.07A \]

4. **Conclusion:**
The peak value of the electric current flowing in the circuit is approximately **7.07 A**.

### Summary of the Solution:
- The RMS current was calculated using Ohm's Law, and then the peak current was derived from the RMS current using the square root of 2.