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The peak value of an alternating emf E g...

The peak value of an alternating emf E given by
`E=(E_0) cos omega t`
is 10V and frequency is 50 Hz. At time `t=(1//600)s` the instantaneous value of emf is

A

`10V`

B

`5sqrt(3)V`

C

`5V`

D

`1V`

Text Solution

Verified by Experts

The correct Answer is:
B
`E=E_(0)cos omegat=E_(0)cos (2pit)/T`
`=10cos.(2pixx50xx1)/600=10cos(pi/6)=5sqrt(3)`volt.
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