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Instantaneous values of current and e.m.f in an AC circuit are `I=I//sqrt(2)sin 314 t` amp and `E=sqrt(2)sin(314t-pi//6)V` respectively. The phase difference between `E` and `I` will be

A

`-pi//6 rad`

B

`-pi//3 rad`

C

`pi//6 rad`

D

`pi//3 rad`

Text Solution

Verified by Experts

The correct Answer is:
A
Phase difference relative to the current
`varphi=(314t-(pi)/6)-(314t)=-(pi)/6`
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