The output current versus time curve of a rectifier is shown in the figure. The voltage value of output current in this case is

Options

A. `0`
B. `(I_(0))/2`
C. `(2I_(0))/(pi)`
D. `I_(0)`

Answer

C

Explanation

`I_(av)=(int_(0)^(T//2) idt)/(int_(0)^(T//2) dt)=(int_(0)^(T//2)I_(0)sin (omegat)dt)/(T//2)`
`=(2I_(0))/T[(-cos omegat)/(omega)]_(0)^(T//2)=(2I_(0))/T[-(cos((omegaT)/2))/(omega)+(cos0^(@))/(omega)]`
`=(2I_(0))/(omegaT)[-cospi+cos^(@)]=(2I_(0))/(2pi)[1+1]=(2I_(0))/(pi)`