A resistance of `40` ohms and an inductance of `95.5` millihenry are connected in series in a `50` cycle/sec AC circuit. The impedance of this combination is very nearly

Options

A. `30 ohm`
B. `40 ohm`
C. `50 ohm`
D. `60 ohm`

Answer

C

Explanation

`Z=sqrt(R^(2)+(2pi vL)^(2))`
`=sqrt((40)^(2)+4pi^(2)xx(50)^(2)xx(95.5xx10^(-3))^(2))=50 ohm`