If an `8Omega` resistance and `6Omega` reactance are present in an AC series circuit then the impedence of the circuit will be

Options

A. `20 ohm`
B. `5 ohm`
C. `10 ohm`
D. `14sqrt(2) ohm`

Explanation

To find the impedance of an AC series circuit with a given resistance and reactance, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the given values:**
- Resistance (R) = 8 Ω
- Reactance (X) = 6 Ω

2. **Use the formula for impedance (Z) in an AC circuit:**
The impedance in a series circuit is given by the formula:
\[ Z = \sqrt{R^2 + X^2} \]

3. **Substitute the values into the formula:**
\[ Z = \sqrt{(8)^2 + (6)^2} \]

4. **Calculate the squares:**
\[ Z = \sqrt{64 + 36} \]

5. **Add the squared values:**
\[ Z = \sqrt{100} \]

6. **Take the square root:**
\[ Z = 10 \, \Omega \]

### Final Answer:
The impedance of the circuit is **10 Ω**.

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