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A resistance of 300Omega and an inductan...

A resistance of `300Omega` and an inductance of `1/(pi)` henry are connected in series to an `AC` voltage of `20 "volts"` and `200Hz` frequency. The phase angle between the voltage and current is

A

`tan^(-1) (4/3)`

B

`tan^(-1) (3/4)`

C

`tan^(-1) (3/2)`

D

`tan^(-1) (2/5)`

Text Solution

Verified by Experts

The correct Answer is:
A
Phase angle `tan varphi=(omegaL)/R=(2pixx200)/300xx1/(pi)=4/3`
`:. varphi=tan^(-1)(4/3)`
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