In the circuit below, the `AC` source the voltage `V=20cos (omegat)` volts with `omega=2000rad//sec`. The amplitude of the current will be nearest to

Options

A. `2A`
B. `3.3 A`
C. `2//sqrt(5)A`
D. `sqrt(5)A`

Answer

A

Explanation

`R=6+4=10 Omega`
`X_(L)=omegaL=2000xx5xx10^(-3)=10Omega`
`X_(C)=1/(omegaC)=1/(2000xx50xx10^(-6))=10 Omega`
`:. Z=sqrt(R^(2)+(X_(L)-X_(C))^(2))=10 Omega`
Amplitude of current `=i_(0)=(V_(0))/Z=20/10=2A`