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A sinusoidal alternating current of peak...

A sinusoidal alternating current of peak value `(I_0)` passes through a heater of resistance R. What is the mean power output of the heater?

A

`I_(0)^(2)R cos theta`

B

`1/2 I_(0)^(2)R`

C

`4/(pi) I_(0)^(2) R`

D

`1/(pi)I_(0)^(2)R`

Text Solution

Verified by Experts

The correct Answer is:
B
Power `=I^(2)R=((I_(p))/(sqrt(2)))^(2) R=(I_(p)^(2)R)/2`
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