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In an a.c. Circuit the voltage applied i...

In an a.c. Circuit the voltage applied is `E=E_(0) sin (omega)t`. The resulting current in the circuit is `I=I_(0)sin((omega)t-(pi/2))`. The power consumption in the circuit is given by

A

`P=(E_(0)I_(0))/(sqrt(2))`

B

`P=sqrt(2) E_(0) I_(0)`

C

`P=(E_(0)I_(0))/2`

D

`P=0`

Text Solution

Verified by Experts

The correct Answer is:
D
Phase angle `varphi=90^(@)`, so power `P=Vi cos varphi=0`
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