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In the circuit of fig, the source freque...

In the circuit of fig, the source frequency is `omega=2000 rad s^(-1)`. The current in the circuit will be

A

`2A`

B

`3.3 A`

C

`2//sqrt(5)A`

D

`sqrt(5)A`

Text Solution

Verified by Experts

The correct Answer is:
A
`L omega=5xx10^(-3)xx2000=10 Omega`
`1/(C omega)=1/(50xx10^(-6)xx2000)=100/10 Omega=10 Omega`
since `L omega=1/(L omega)`,
`:. Z=R=0.10+4=10.1 Omega`
`I_(0)=E/Z=20/10.1 A=2A`
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