In the circuit shown here, `R` is pure resistor, `L` is an inductor of negligible resistance (as compared to `R`), `S` is a `100 V, 50Hz AC` source of negligible resistance. With either key `K_(1)` alone or `K_(2)` alone closed, the current is `I_(0)`. if the source is changed to `100 V, 150 Hz` the current with `K_(1)`, alone closed and with `K_(2)` alone closed will be respectively.

Options

A. `I_(0),(I_(0))/3`
B. `I_(0),3I_(0)`
C. `3I_(0),I_(0)`
D. `3I_(0), (I_(0))/3`

Answer

A

Explanation

With the change in frequency, current remains unchanged in `R`. However, it becomes one-third in `L`.