A 220-V, 50 Hz, ac generator is connected to an inductor and a `50 Omega` resistance in series. The current in the circuit is `1.0 A`. What is the PD across inductor?

Options

A. `102.2 V`
B. `186.4V`
C. `213.6V`
D. `302V`

Answer

C

Explanation

`I=E/Z, I=220/Z,Z=220 Omega`
`Z^(2)=R^(2)+X_(L)^(2) :. X_(L)=sqrt(Z^(2)-R^(2))`
`L=1/(omega)sqrt(Z^(2)-R^(2))`
`L=1/(2pif)sqrt(Z^(2)-R^(2))=0.68 H`
`:. V_(L)=omegaLI=2pixx0.5xx0.68xx1`
`=213.6 V`