An `8 muF` capacitor is connected across a 220 V, 50 Hz line. What is the peak value of charge through the capacitor?

Options

A. `2.5xx10^(-3) C`
B. `2.5xx10^(-4) C`
C. `5xx10^(-5) C`
D. `7.5xx10^(-2) C`

Answer

A

Explanation

`X_(c)=1/(omegaC)=1/(2pixx50xx8xx10^(-6))=398 Omega`
`V_(r.m.s.)=220V, V_(peak)=sqrt(2xx220)=311 V`
`q_(rms)=V_(rms)C=1.76xx10^(-3)C`
`q_(peak)=sqrt(2)q_(rms)=1.76xx10^(-3)xxsqrt(2)=2.5xx10^(-3)C`