A `500 Omega` resistor and a capacitor `C` are connected in series across `50 Hz AC` supply mains. The r.m.s potential difference recorded on voltmeter `V_(1)` and `V_(2)` are `V_(1)=120 V` and `V_(2)=160 V`. The power taken for the mains is:

Options

A. `480 W`
B. `240 W`
C. `28.8 W`
D. `14.4 W`

Answer

C

Explanation

`V_(r.m.s)sqrt(V_(1)^(2)+V_(2)^(2))=sqrt(120^(2)+160^(2))`
`I_(V)xx500=120, I_(V)=24A`
`P_(av)=I_(V)^(2)R`