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A circuit has a resistance of 11 Omega, ...

A circuit has a resistance of `11 Omega`, an inductive reactance of `25 Omega`, and a capacitive resistance of `18 Omega`. It is connected to an `AC` source of `260 V` and `50 Hz`. The current through the circuit (in amperes) is

A

`11`

B

`15`

C

`18`

D

`20`

Text Solution

Verified by Experts

The correct Answer is:
D
`Z=sqrt(R^(2)+(X_(L)-X_(C))^(2))`
`=sqrt((11)^(2)+(25-18)^(2))=13 Omega`
Current `i=260/13 =20A`
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