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A clock hung on a wall has marks instead...

A clock hung on a wall has marks instead of numerals in its dial. On the adjoining wall, there is a plane mirror and the image of the clock in the mirror indicates the time `4.20`. Then the time on the clock is

A

`7.40`

B

`4.20`

C

`2.40`

D

`4.07`

Text Solution

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The correct Answer is:
To determine the actual time on the clock when the mirror shows the time as 4:20, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Problem**: We have a clock showing a time of 4:20 in the mirror. We need to find out what time it actually is on the clock. 2. **Visualize the Clock**: Draw a simple clock face. Mark the positions of the hour and minute hands at 4:20. The minute hand will be on the 4 (indicating 20 minutes past the hour), and the hour hand will be slightly past the 4. 3. **Mirror Reflection**: When you look at the clock in the mirror, the positions of the hands will appear reversed. The minute hand at 20 minutes will appear at 40 minutes on the clock face (since 60 - 20 = 40). The hour hand will also be reflected. 4. **Calculate the Actual Time**: To find the actual time on the clock, we can use the formula: \[ \text{Actual Time} = 12:00 - \text{Mirror Time} \] Here, the mirror time is 4:20. 5. **Perform the Calculation**: - Convert 4:20 into a 12-hour format: - 4:20 in the mirror means the hour hand is between 4 and 5, and the minute hand is at 4 (20 minutes). - Now, apply the formula: \[ \text{Actual Time} = 12:00 - 4:20 \] - To subtract, we can convert 4:20 into minutes: - 4 hours = 240 minutes - 20 minutes = 20 minutes - Total = 240 + 20 = 260 minutes - Now, convert 12:00 into minutes: - 12 hours = 720 minutes - Now perform the subtraction: \[ 720 - 260 = 460 \text{ minutes} \] - Convert 460 minutes back into hours and minutes: - 460 minutes = 7 hours and 40 minutes (since 7 hours = 420 minutes and 40 minutes = 40 minutes) - Therefore, the actual time on the clock is: \[ 7:40 \] ### Final Answer: The time on the clock is **7:40**. ---

To determine the actual time on the clock when the mirror shows the time as 4:20, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Problem**: We have a clock showing a time of 4:20 in the mirror. We need to find out what time it actually is on the clock. 2. **Visualize the Clock**: Draw a simple clock face. Mark the positions of the hour and minute hands at 4:20. The minute hand will be on the 4 (indicating 20 minutes past the hour), and the hour hand will be slightly past the 4. ...
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A2Z-GEOMETRICAL OPTICS-Section D - Chapter End Test
  1. A clock hung on a wall has marks instead of numerals in its dial. On ...

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  2. Wavelength of light used in an optical instrument are lambda(1)=400 Å ...

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  3. A plano convex lens of refractive index 1.5 and radius of curvature 30...

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  4. A light ray is incident perpendicularly to one face of a 90^circ prism...

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  5. A thin glass (refractive index 1.5) lens has optical power of -5D in a...

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  6. Which of the following graphs is the magnification of a real image aga...

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  7. A thin prism P(1) with angle 4degree and made from glass of refractive...

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  8. A converging lens is used to form an image on a screen. When the upper...

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  9. A diminished image of an object is to be obtained on a screen 1.0 m fr...

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  10. An object 15cm high is placed 10cm from the optical center of a thin l...

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  11. A lens forms a virtual, diminished image of an object placed at 2 m fr...

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  12. When the distance between the object and the screen is more than 4 f....

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  13. a convex lens of power +6 diopter is placed in contact with a concave ...

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  14. A concave lens of focal length 20 cm product an image half in size of ...

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  15. A convex lens of focal length 1.0m and a concave lens of focal length ...

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  16. If in a planoconvex lens, the radius of curvature of the convex surfac...

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  17. A convex lens A of focal length 20cm and a concave lens G of focal le...

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  18. The radii of curvature of the two surfaces of a lens are 20cm and 30 c...

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  19. A lens forms a virtual image 4 cm away from it when an object is place...

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  20. A concave lens of focal length (1)/(3)m forms a real, inverted image t...

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  21. An object is placed at a distance of f//2 from a convex lens. The imag...

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