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The true value of angle of dip at a plac...

The true value of angle of dip at a place is 60^(@)`, the apparent dip in a inclined at an angle of `30^(@)` with magnetic meridian is

A

`tan^(-1)"(1)/2

B

`tan^(-1)(2)`

C

`tan^(-1)"(2/3)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B

`tan varphi^(')=(tan varphi)/(cos beta)`, where `varphi^(')`= Apparent angle of dip,
`varphi`= True angle of dip, `beta`= Angle made by vertical plane with magnetic meridian.
`impliestan varphi^(')= (tan 60^(@))/(cos 30^(@))=2implies varphi^(')=tan^(-1)(2)`
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Knowledge Check

  • The true value of dip at a place is 60^(@) . The apparent dip in a plane inclined at an angle of 30^(@) with magnetic meridian is

    A
    `tan^(1) (1/2)`
    B
    `tan^(-1) (2)`
    C
    `tan^(-1)(2/3)`
    D
    None of these
  • The true value of angle of dip at a place is 60^(@) . The apparent angle of dip , when a magnetic needle is rotated through 30^(@) from the magnetic meridian at the same place , is

    A
    `tan^(-1) (2)`
    B
    `tan ^(-1) ((1)/(2))`
    C
    `tan^(-1) ((3)/(2))`
    D
    `tan^(-1) ((4)/(3))`
  • At a place dip angle is known to be 45 ^(@). The apparent dip when dip circle is placed at an angle of 60^(@) with the magnetic meridian will be

    A
    `tan ^(-1) (2)`
    B
    `tan ^(-1) ((1)/(2))`
    C
    `tan ^(-1) (sqrt2)`
    D
    `tan ^(-1) ((1)/(sqrt2))`
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