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What should be the angle between two pla...

What should be the angle between two plane mirrors so that whatever be the angle of incidence, the incident ray and the reflected ray from the two mirrors be parallel to each other

A

`60^(@)`

B

`90^(@)`

C

`120^(@)`

D

`175^(@)`

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The correct Answer is:
To find the angle between two plane mirrors such that the incident ray and the reflected ray from the two mirrors are parallel to each other, we can follow these steps: ### Step 1: Define the Angles Let the angle between the two mirrors be denoted as θ. When a ray of light strikes the first mirror, it makes an angle of incidence, which we will denote as θ₁. ### Step 2: Reflection from the First Mirror According to the law of reflection, the angle of reflection is equal to the angle of incidence. Therefore, the angle of reflection from the first mirror will also be θ₁. ### Step 3: Incident Ray on the Second Mirror When the reflected ray from the first mirror strikes the second mirror, it will also make an angle θ₂ with the normal to the second mirror. Since the two mirrors are at an angle θ to each other, we can relate θ₁ and θ₂. ### Step 4: Relationship Between Angles For the reflected ray from the first mirror and the incident ray on the second mirror to be parallel, the sum of the angles must equal 180 degrees. Thus, we can write: \[ 2θ₁ + 2θ₂ = 180° \] From this, we can simplify to: \[ θ₁ + θ₂ = 90° \] ### Step 5: Expressing θ₂ in Terms of θ₁ From the equation \( θ₁ + θ₂ = 90° \), we can express \( θ₂ \) as: \[ θ₂ = 90° - θ₁ \] ### Step 6: Analyzing the Geometry Now, we need to consider the geometry of the situation. The angle between the two mirrors (θ) can be expressed in terms of θ₁ and θ₂. The relationship can be derived from the triangle formed by the angles: \[ θ₁ + θ + θ₂ = 180° \] Substituting \( θ₂ = 90° - θ₁ \) into this equation gives: \[ θ₁ + θ + (90° - θ₁) = 180° \] ### Step 7: Simplifying the Equation This simplifies to: \[ θ + 90° = 180° \] From which we can conclude: \[ θ = 90° \] ### Conclusion Thus, the angle between the two plane mirrors should be **90 degrees** for the incident ray and the reflected ray from the two mirrors to be parallel to each other. ---

To find the angle between two plane mirrors such that the incident ray and the reflected ray from the two mirrors are parallel to each other, we can follow these steps: ### Step 1: Define the Angles Let the angle between the two mirrors be denoted as θ. When a ray of light strikes the first mirror, it makes an angle of incidence, which we will denote as θ₁. ### Step 2: Reflection from the First Mirror According to the law of reflection, the angle of reflection is equal to the angle of incidence. Therefore, the angle of reflection from the first mirror will also be θ₁. ...
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A2Z-GEOMETRICAL OPTICS-Section D - Chapter End Test
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  2. Wavelength of light used in an optical instrument are lambda(1)=400 Å ...

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  3. A plano convex lens of refractive index 1.5 and radius of curvature 30...

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  4. A light ray is incident perpendicularly to one face of a 90^circ prism...

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  5. A thin glass (refractive index 1.5) lens has optical power of -5D in a...

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  6. Which of the following graphs is the magnification of a real image aga...

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  7. A thin prism P(1) with angle 4degree and made from glass of refractive...

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  8. A converging lens is used to form an image on a screen. When the upper...

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  9. A diminished image of an object is to be obtained on a screen 1.0 m fr...

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  10. An object 15cm high is placed 10cm from the optical center of a thin l...

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  11. A lens forms a virtual, diminished image of an object placed at 2 m fr...

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  12. When the distance between the object and the screen is more than 4 f....

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  13. a convex lens of power +6 diopter is placed in contact with a concave ...

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  14. A concave lens of focal length 20 cm product an image half in size of ...

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  15. A convex lens of focal length 1.0m and a concave lens of focal length ...

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  16. If in a planoconvex lens, the radius of curvature of the convex surfac...

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  17. A convex lens A of focal length 20cm and a concave lens G of focal le...

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  18. The radii of curvature of the two surfaces of a lens are 20cm and 30 c...

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  19. A lens forms a virtual image 4 cm away from it when an object is place...

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  20. A concave lens of focal length (1)/(3)m forms a real, inverted image t...

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  21. An object is placed at a distance of f//2 from a convex lens. The imag...

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