Home
Class 12
PHYSICS
With a concave mirror, an object is plac...

With a concave mirror, an object is placed at a distance `x_(1)` from the principal focus, on the principal axis. The image is formed at a distance `x_(2)` from the principal focus. The focal length of the mirror is

A

`x_(1)x_(2)`

B

`(x_(1)+x_(2))/(2)`

C

`sqrt((x_(1))/(x_(2)))`

D

`sqrt(x_(1)x_(2))`

Text Solution

AI Generated Solution

The correct Answer is:
To find the focal length of a concave mirror when the object is placed at a distance \( x_1 \) from the principal focus and the image is formed at a distance \( x_2 \) from the principal focus, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the distances**: - Let the focal length of the mirror be \( f \). - The object distance \( u \) from the mirror is given by: \[ u = f + x_1 \] - The image distance \( v \) from the mirror is given by: \[ v = f + x_2 \] 2. **Use the mirror formula**: The mirror formula relates the object distance \( u \), the image distance \( v \), and the focal length \( f \): \[ \frac{1}{f} = \frac{1}{u} + \frac{1}{v} \] 3. **Substitute the values of \( u \) and \( v \)**: Substituting the expressions for \( u \) and \( v \) into the mirror formula gives: \[ \frac{1}{f} = \frac{1}{f + x_1} + \frac{1}{f + x_2} \] 4. **Find a common denominator**: The common denominator for the right-hand side is \( (f + x_1)(f + x_2) \): \[ \frac{1}{f} = \frac{(f + x_2) + (f + x_1)}{(f + x_1)(f + x_2)} \] Simplifying the numerator: \[ \frac{1}{f} = \frac{2f + x_1 + x_2}{(f + x_1)(f + x_2)} \] 5. **Cross-multiply to eliminate the fractions**: Cross-multiplying gives: \[ (f + x_1)(f + x_2) = f(2f + x_1 + x_2) \] 6. **Expand both sides**: Expanding the left-hand side: \[ f^2 + (x_1 + x_2)f + x_1x_2 = 2f^2 + f(x_1 + x_2) \] 7. **Rearranging the equation**: Rearranging the equation results in: \[ f^2 + (x_1 + x_2)f + x_1x_2 - 2f^2 - f(x_1 + x_2) = 0 \] Simplifying gives: \[ -f^2 + x_1x_2 = 0 \] or \[ f^2 = x_1x_2 \] 8. **Taking the square root**: Finally, taking the square root of both sides yields: \[ f = \sqrt{x_1 x_2} \] ### Final Answer: The focal length of the concave mirror is: \[ f = \sqrt{x_1 x_2} \]

To find the focal length of a concave mirror when the object is placed at a distance \( x_1 \) from the principal focus and the image is formed at a distance \( x_2 \) from the principal focus, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the distances**: - Let the focal length of the mirror be \( f \). - The object distance \( u \) from the mirror is given by: \[ ...
Promotional Banner

Topper's Solved these Questions

  • GEOMETRICAL OPTICS

    A2Z|Exercise Refraction At Curved Surface|64 Videos
  • GEOMETRICAL OPTICS

    A2Z|Exercise Prism Theory And Dispersion Of Light|45 Videos
  • ELECTROMAGNETIC WAVES AND COMMUNICATION SYSTEM

    A2Z|Exercise Section D - Chapter End Test|30 Videos
  • MAGNETISM AND MATTER

    A2Z|Exercise Section D - Chapter End Test|30 Videos

Similar Questions

Explore conceptually related problems

With a concave mirror, an object is placed at a distance 9cm from the principal focus, on the principal axis. The image is formed at a distance 16cm from the principal focus. The focal length of the mirror is

An object is placed at a distance x_1 from the principal focus of a lens and its real image is formed at a distance x_2 from the another principal focus. The focal length of the lens is

In a concave mirror, an object is placed at a distance d_1 from the focus and the real image is formed aat a distance d_2 from the focus. Then the focal length of the mirror is :

In a concave mirrorr experiment, an object is placed at a distance x_(1) from the focus and the image is formed at a distance x_(2) from the focus. The focus length of the mirrorr would be

An object placed at a distance of a 9cm from the first principal focus of a convex lens produces a real image at a distance of 25cm. from its second principal focus. then the focal length of the lens is :

Define the principal focus of a spherical mirror.

In case of thin lens of focal length f an object is placed at a distance x_(1) from first focus and its image is formed at a distance x_(2) from the second focus, find x_(1) x_(2)

The magnificationof the image when an object is placed at a distance x from the principle focus of a mirror of focal length f is

A2Z-GEOMETRICAL OPTICS-Section D - Chapter End Test
  1. With a concave mirror, an object is placed at a distance x(1) from the...

    Text Solution

    |

  2. Wavelength of light used in an optical instrument are lambda(1)=400 Å ...

    Text Solution

    |

  3. A plano convex lens of refractive index 1.5 and radius of curvature 30...

    Text Solution

    |

  4. A light ray is incident perpendicularly to one face of a 90^circ prism...

    Text Solution

    |

  5. A thin glass (refractive index 1.5) lens has optical power of -5D in a...

    Text Solution

    |

  6. Which of the following graphs is the magnification of a real image aga...

    Text Solution

    |

  7. A thin prism P(1) with angle 4degree and made from glass of refractive...

    Text Solution

    |

  8. A converging lens is used to form an image on a screen. When the upper...

    Text Solution

    |

  9. A diminished image of an object is to be obtained on a screen 1.0 m fr...

    Text Solution

    |

  10. An object 15cm high is placed 10cm from the optical center of a thin l...

    Text Solution

    |

  11. A lens forms a virtual, diminished image of an object placed at 2 m fr...

    Text Solution

    |

  12. When the distance between the object and the screen is more than 4 f....

    Text Solution

    |

  13. a convex lens of power +6 diopter is placed in contact with a concave ...

    Text Solution

    |

  14. A concave lens of focal length 20 cm product an image half in size of ...

    Text Solution

    |

  15. A convex lens of focal length 1.0m and a concave lens of focal length ...

    Text Solution

    |

  16. If in a planoconvex lens, the radius of curvature of the convex surfac...

    Text Solution

    |

  17. A convex lens A of focal length 20cm and a concave lens G of focal le...

    Text Solution

    |

  18. The radii of curvature of the two surfaces of a lens are 20cm and 30 c...

    Text Solution

    |

  19. A lens forms a virtual image 4 cm away from it when an object is place...

    Text Solution

    |

  20. A concave lens of focal length (1)/(3)m forms a real, inverted image t...

    Text Solution

    |

  21. An object is placed at a distance of f//2 from a convex lens. The imag...

    Text Solution

    |