An object ABED is placed in front of a concave mirror beyond the center of curvature C as shown in figure., State the shape of the image.

Options

A. `|m_(AB)|lt1 and |m_(ED)|lt1`
B. `|m_(AB)|gt1 and |m_(ED)|lt1`
C. `|m_(AB)|lt1 and |m_(ED)|gt1`
D. `|m_(AB)|gt1 and |m_(ED)|gt1`

Answer

A

Explanation

Object is place beyond `C`. Hence, the image will be real and it will lie between `C` and `F`. Further `u,v` are negative, hence the mirrorr.
Formula will become
`(1)/(v)+(1)/(u)=(1)/(f)`
`(1)/(v)+(1)/(u)=(1)/(f)=(u-f)/(uf)` or `v=(f)/(1-(f//u))`
Now `u_(AB)gtu_(ED)`
`:.v_(AB)gtv_(ED)`
`|m_(AB)|lt|m_(ED)|` (a as `m=-(v)/(m)`)
Therefore, shape of the image will be as shown in figure.
Also note that, `v_(AB) lt u_(AB)` and `v_(ED) lt u_(ED)`
So, `|m_(AB)|lt1` and `|m_(ED)|lt1`