An electron in hydrogen atom after absorbing an energy photon jumps from energy state `n_(1)` to `n_(2)`. Then it returns to ground state after emitting six different wavelength in emission spectrum. The energy of emitted photons is either equal to, less than or greater than the absorbed photons. then `n_(1)` and `n_(2)` are

Options

A. `n_(1) = 5, n_(2) = 3`
B. `n_(1) = 5, n_(2) = 2`
C. `n_(1) =4, n_(2) = 3`
D. `n_(1) = 4, n_(2) = 2`

Answer

D

Explanation

As the electron returns to ground state after emitting six different wavelengths in emission spectrum, there must be a difference of '2' between the ground and excited states.
Also the ground state should be `n = 2`.
Hence `n_(1) = 4, n_(2) = 2`.