Imagine an atom made up of a proton and a hypotnerical particle of double the mass of the electron but having the same charge as the electron. Apply the Bohr atom model and consider all possible transitions of this hypotnetical photon that will be emitted has wavelength `lambda` (given in terms of the Rydberg constant `R` for the hydrogen atom) equal to

Options

A. `9//(5R)`
B. `36//(5R)`
C. `18//(5R)`
D. `4//R`

Answer

C

Explanation

In hydrogen atom `E_(n) =- (Rhc)/(n^(2))`
Also `E_(n) prop m`, where `m` is the mass of th electron. Here the electron has been replaced by a particle whose mass is double of an electron. Therefore, for this hypothetical atom energy in `nth` orbit will be
given by `E_(n) =- (2Rhc)/(n^(2))`
This given `lambda_(max) = (18)/(5R)`.