If we assume that perptraing power of any radiation/particle is inversely proportional to its de-Broglie wavelength of the particle then:

Options

A. A proton and an `alpha`-particle after getting accelerated thorugh same potential difference will have equal penetrating power.
B. Penerating power of `alpha-`particle will be greater than hat of proton which have been accelerated by same potential difference.
C. Protons' penetrating power will be less than pentrating power of an electron which has been accelerated by the same potetnial difference.
D. Pentrating powers cannot be compared as all these are partcles having no wavelength or wave nature.

Answer

B

Explanation

`lambda = (h)/(p) = (h)/(sqrt(2mE)) rArr (h)/(sqrt(2m(Vq)))`
`:.` For higher `m` and `q`,
`lambda` will be smaller.
For an 'alpha' particle, both 'm' and 'q' are higher. ltbRgt Hence, lesser is the wavelength.
As, (Penetrating power) `prop` Energy `prop (1)/(lambda)`
From, above, penetrating power of an `alpha`-particle is more than that of a proton.