Two hydrogen atoms are in excited state ...

Two hydrogen atoms are in excited state with electrons in`n=2` state.First one is moving to wards left and emits a photon.' of energy `E_(1)` towards right. Second one is moving towards right with same speed and emits a photon of energy `E_(2)` towards right. Taking recoil of nucleus.into account during_emission process :

`E_(1) gt E_(2)`

`E_(1) lt E_(2)`

`E_(1) = E_(2)`

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The correct Answer is:

In the first case `K.E.` of `H`-atom increases due to recoil whereas in the second case `K.E.` decreases due to recoil.
`:. E_(2) gt E_(1)`

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