What is the angular momentum of an electron in Bohr's hydrogen atom whose energy is `-0.544 eV`?

Options

A. `(h)/(pi)`
B. `(2h)/(pi)`
C. `(5h)/(pi)`
D. `(7h)/(pi)`

Answer

C

Explanation

By using `E =- (13.6)/(n^(2))eV` (for `H_(2)` atom)
`rArr -0.544 =- (13.6)/(n^(2)) rArr n^(2) = 25 rArr n = 5`
`:.` Angualr momentum `n(h)/(2pi) =(5h)/(2pi)`