Consider `3rd` orbit of `He^(+)` (Helium) using nonrelativistic approach the speed of electron in this orbit will be (given `K = 9 xx 10^(9)` constant `Z = 2` and `h` (Planck's constant) `= 6.6 xx 10^(-34)Js`.)

Options

A. `2.92 xx 10^(6)m//s`
B. `1.46 xx 10^(6)m//s`
C. `0.73 xx 10^(6)m//s`
D. `3.0 xx 10^(8)m//s`

Answer

B

Explanation

Speed of electron in `nth` orbit `V = (C )/(137) xx (Z)/(n)`
`V = (300)/(137) xx (2)/(3) xx 10^(6)`
`V = (200)/(137) xx 10^(6) m//s = 1.46 xx 10^(6)m//s`