An energy of `24.6 eV` is required to remove one of that electrons from a neutal helium atom. The enegy (in `eV`)required to remove both the electrons from a netural helium atom is

Options

A. `79.0`
B. `51.8`
C. `49.2`
D. `38.2`

Answer

A

Explanation

After the removed of first electron remaining atom will be hydrogen-like atom.
So enegry required to remove second electron from the atom `E = 13.6 xx (2^(2))/(1) = 54.4 eV`
`:.` Total enegry required `= 24.6 + 54.4 = 79eV`.