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An electron in H atom makes a transition...

An electron in `H` atom makes a transition from `n = 3` to `n = 1`. The recoil momentum of the `H` atom will be

A

`6.45 xx 10^(-27) Ns`

B

`6.8 xx 10^(-27) Ns`

C

`6.45 xx 10^(-24) Ns`

D

`6.8 xx 10^(-24) Ns`

Text Solution

Verified by Experts

The correct Answer is:
A

Recoil momentum `= (DeltaE)/(c )`
`DeltaE =- (13.6)/(9)-(-(13.6)/(1))`
`=13.6 - (13.6)/(9)`
`= (8xx13.6)/(9)eV = 12.09eV`.
`(DeltaE)/(c ) = (12.09xx1.6xx10^(-10))/(3xx10^(8))Ns`
`= 6.45xx10^(-27) Ns`
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