In hydrogen atom, the transition takes place from `n = 3` to `n = 2`. If Rydberg's constant is `1.09 xx 10` per metre, the wavelength of the limit emitted is

Options

A. `6606 Å`
B. `4861 Å`
C. `4340 Å`
D. `4101 Å`

Answer

A

Explanation

`(1)/(lambda) = 1.09 xx 10^(7) [(1)/(2^(2))-(1)/(3^(2))]`
`(1)/(lambda) = 1.09 xx 10^(7)[(1)/(4)-(1)/(9)]`
`(1)/(lambda) = 1.09 xx 10^(7) xx (5)/(36)m`
or `lambda = (36xx10^(10))/(5xx1.09xx10^(7)) Å = 6606 Å`